Solving Reaction Forces: Simplifying Complex Torque and Force Equations

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Homework Help Overview

The original poster presents a problem involving the calculation of reaction forces, simplified to a set of torque and force equations. The context appears to involve symmetry and possibly a physical structure, as indicated by the provided diagrams.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants inquire about the specific nature of the problem and the diagrams, seeking clarification on what is being represented and the context of the reaction forces. There are discussions about the symmetry of the forces and their distances to points A and B.

Discussion Status

The discussion is ongoing, with participants asking for clarification and additional information to better understand the problem setup. There is no clear consensus yet, as the original poster has not fully articulated the problem or provided all necessary details.

Contextual Notes

Some participants note the absence of a complete diagram, which may hinder understanding. The original poster has acknowledged this by attempting to provide additional images.

Lorens
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I have a problem which i ahve simplified to this

http://img63.imageshack.us/img63/3998/bigproblem7hg.jpg

I want to calculate the reaction forces but how?

Torque equation give this
2F=0
Force equations give this
2F=0

Thx for any help given ...
 
Last edited by a moderator:
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The problem look like this in reality (symmetry)

http://img481.imageshack.us/img481/811/a19nx.jpg
 
Last edited by a moderator:
Can you state the problem? I don't understand what those diagrams represent. You are trying to find the reaction forces of what?
 
Doc Al said:
Can you state the problem? I don't understand what those diagrams represent. You are trying to find the reaction forces of what?

A and B ...
 
The force have the same distance to a and b
 
Ups i may have forgotten to add the picture
http://img68.imageshack.us/img68/3416/tank15jc.jpg
 
Last edited by a moderator:

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