Solving Resonance: Ideas to Get Started

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SUMMARY

The discussion centers on determining the resonant frequency of a 143-cm-long pipe that is closed at one end and has a loudspeaker at the open end. The relevant equation for this problem is frequency (f) equals velocity (v) divided by wavelength (λ), specifically for sound waves traveling at 343 m/s. The key point of confusion is whether the resonant frequency occurs at 1/4, 1/2, or 1 wavelength of the pipe's length. Understanding these concepts is essential for solving the problem effectively.

PREREQUISITES
  • Understanding of wave properties, specifically wavelength and frequency.
  • Familiarity with the speed of sound in air (343 m/s).
  • Knowledge of resonance in closed-end pipes.
  • Basic algebra for manipulating equations.
NEXT STEPS
  • Study the principles of resonance in closed pipes and how they differ from open pipes.
  • Learn how to calculate wavelength using the formula λ = v/f.
  • Explore the relationship between frequency and harmonics in acoustic systems.
  • Investigate the effects of varying frequency on sound waves in different mediums.
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics and acoustics, as well as educators looking for teaching strategies related to sound and resonance.

LTU83
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I don't want the answer to this problem just an idea of how to get started. I don't understand what I am looking for. Thanks.

Homework Statement



A 143-cm-long pipe is stopped at one end. Near the open end, there is a loudspeaker that is driven by an audio oscillator whose frequency can be varied from 10.0 to 4700 Hz. (Take the speed of sound to be 343 m/s.)


Homework Equations


freq= v / λ (just guessing)


The Attempt at a Solution

 
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I don't understand what you are looking for either. There is no question attached to the statement of the situation, but f = v/λ is correct regardless.
 
I presume you want to find the resonant frequency of the pipe. Let's narrow it down a bit. Will it be when the length of the pipe is equal to 1/4 wavelength, 1/2 wavelength or 1 wavelength of the frequency?
 

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