What Is the Correct Water Level for the Third Resonance in a Closed-Open Tube?

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Homework Help Overview

The problem involves determining the water level for the third resonance in a closed-open tube when a tuning fork of frequency 512 Hz is used. The context includes the behavior of sound waves in a tube with one end closed and the other open, and the speed of sound in air is given as 343 m/s.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the wavelength and frequency formulas for closed-open tubes, with one participant attempting to calculate the water level for the third resonance using the provided frequency and speed of sound. Others question the validity of using n=3 for the third resonance and suggest drawing diagrams to visualize standing waves.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the resonance levels and questioning the assumptions made about the value of n in the resonance formula. Some guidance has been offered regarding the relationship between water levels and resonance positions, but no consensus has been reached.

Contextual Notes

There is a noted confusion regarding the definition of the "third resonance" and how it relates to the values of n in the equations used. Participants are also considering the implications of drawing diagrams to aid in understanding the standing wave patterns in the tube.

Any Help
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Homework Statement



A vibrating tuning fork of frequency 512 Hz is held over a water column with one end closed and the other open. As the water level is allowed to fall, a loud sound (resonance) is heard at specific water levels. Assume you start with the tube full of water, and begin steadily lowering the water level. What is the water level (as measured from the top of the tube) for the third such resonance? Take the speed of sound in air to be 343 m/s.


  • A

    83.7 cm


  • B

    16.7 cm

  • C

    33.5 cm
  • wrong-icon.png


    D

    50.2 cm


  • E

    167 cm

Homework Equations



in a fundamental frequency (f):
λ=2L/n and f=n/2L .v for waves whose both ends are open
λ=4L/n and f=n/4L .v for waves whose one end closed and the second is open
n is a positive integer; n= 0,1,2,3,4,5,6...
v is the velocity
L is the length of string
λ is the wavelength

The Attempt at a Solution


here we have one open and other closed ends then we use λ=4L/n and f=n/4L .v
so f=512Hz, n=3 (third such resonance) and v=343m/sec
substitute in the equation
we get L equal 0.502m=50.2cm then it is D
but why the correct answer is A??
 
Last edited by a moderator:
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n = 3 is incorrect. The best thing to do for these types of problems is to draw a diagram of the standing wave for the situation. You can then determine L from the diagram.
 
Last edited:
TSny said:
n = 3 is incorrect. The best thing to for these types of problems is to draw a diagram of the standing wave for the situation. You can then determine L from the diagram.
I didn't get your point. How can I draw diagram for it? Besides why n=3 is not correct? what do they mean by the third such resonance?
 
Any Help said:
How can I draw diagram for it?
When the level of the water is at a position of resonance, what can you say about the positions of nodes and antinodes, especially at the top of the tube and at the top of the water? You can use this knowledge as a guide for drawing the various cases where you get resonance.
Besides why n=3 is not correct?
The n in the formula does not necessarily correspond to the number of the resonance. Thus n = 3 does not correspond to the third resonance in your situation.
What do they mean by the third such resonance?
Imagine the water level starts at the top of the tube. As the level of the water is lowered in the tube while the fork is vibrating, there will be certain positions of the level of the water that will cause the sound from the fork to resonate. The first level that produces a resonance is the first resonance. The next level of water that produces resonance is the second resonance. And so on.
 
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