# Solving Schrodinger's Equation: Finite Jumps at Singular Points?

• RedX
In summary: This is because the equation is only valid if both sides are non-zero. In summary, when solving Schrodinger's equation, it is possible for the derivative of the wave function to have a finite jump if the potential is infinity at a certain point. However, this assumption is based on the wave function not going to zero, and in general, a finite jump cannot be assumed when f(x) is singular at x_0. The easiest case to observe this is in the infinite well, where the solution has a finite jump in its slope at the boundary, but the wave function itself is zero at the boundary.
RedX
When solving Schrodinger's eqn. one comes across the expression:

$$\frac{d^2 \psi}{dx^2}=(V-E)\psi$$

where the mass has been chosen to make $$\frac{\hbar^2}{2m}=1$$

If V is infinity at some x, then it is said that $$\frac{d \psi}{dx}$$ can have a finite jump at that x, since $$\frac{d^2 \psi}{dx^2}=\infty$$

But doesn't this assume that $$\psi$$ doesn't go to zero? Then you would get: $$\frac{d^2 \psi}{dx^2}=(V-E)\psi=\infty*0$$ and it is not necessarily true that $$\frac{d^2 \psi}{dx^2}=\infty$$, hence no longer necessarily true that $$\frac{d \psi}{dx}$$ can have a finite jump.

The easiest case is the infinite well. The solution at the boundary of the well does have a finite jump in its slope. However, the function $$\psi$$ itself is zero at the boundaries of the well.

So in general, if you have a differential equation $$y'=f(x)y$$, where f(x) is singular at a point $$x_0$$, can you assume a finite jump in the solution y at $$x=x_0$$?

No, you cannot assume a finite jump in the solution y at x=x_0. This is because the equation y'=f(x)y only holds if both y and f(x) are non-zero. If f(x) is singular at x_0, then it is not necessarily true that y will have a finite jump at x_0.

I would approach this question by first examining the assumptions and definitions being made. It is important to understand that the Schrodinger's equation is a mathematical model used to describe the behavior of quantum particles. It is based on certain assumptions and approximations, and therefore it may not always accurately reflect the physical reality.

In this case, the assumption that V is infinity at some x implies a singularity in the potential energy. This singularity is not physical, but rather a mathematical representation of a point where the potential energy becomes infinitely large. Therefore, it is important to consider the limitations of the model and not make assumptions that may not hold in the physical world.

Furthermore, the statement that \frac{d \psi}{dx} can have a finite jump at x implies that \psi is continuous at that point. However, as noted in the example of the infinite well, \psi can actually be zero at the boundaries of the well. This means that \psi is not continuous at those points and therefore the assumption of a finite jump in \frac{d \psi}{dx} may not hold.

In general, when dealing with singular points in a differential equation, it is important to carefully consider the assumptions and limitations of the model being used. It may not always be appropriate to assume a finite jump in the solution at a singular point, and further analysis and understanding of the physical system may be necessary.

In summary, while the Schrodinger's equation is a powerful tool for understanding the behavior of quantum particles, it is important to approach it with caution and not make assumptions that may not hold in the physical world. Further research and analysis may be needed to fully understand the implications of singular points in the equation.

## 1. What is Schrodinger's equation?

Schrodinger's equation is a fundamental equation in quantum mechanics that describes the time evolution of a quantum system. It is a differential equation that relates the wave function of a particle to its potential energy.

## 2. What do you mean by "finite jumps at singular points"?

In quantum mechanics, the wave function of a particle is continuous everywhere except at certain points where it experiences a sudden, finite jump. These points are known as singular points.

## 3. Why are finite jumps at singular points important in solving Schrodinger's equation?

Finite jumps at singular points play a crucial role in understanding the behavior of quantum particles. They allow us to explain phenomena such as tunneling and quantization, which cannot be explained by classical mechanics.

## 4. How do scientists solve Schrodinger's equation for systems with finite jumps at singular points?

There are various mathematical and numerical techniques used to solve Schrodinger's equation for systems with finite jumps at singular points. These include perturbation theory, variational methods, and numerical methods such as the finite element method.

## 5. What are some practical applications of solving Schrodinger's equation with finite jumps at singular points?

Solving Schrodinger's equation with finite jumps at singular points has numerous applications in fields such as physics, chemistry, and engineering. It is used to understand the behavior of atoms, molecules, and materials at the quantum level, and has practical applications in fields such as semiconductors, lasers, and quantum computing.

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