- #1

chwala

Gold Member

- 871

- 70

3^x . 2^x+y = 3^x . 6^y

3^x. 2^x+y = 6(2^y). 2^x+y on subtraction

i get

3^x.6^y - 6(2^y).2^x+y = 0 then

3^x. 6^y = 6(2^y). 2^x. 2^y on solving i get

x log (3/2)= log 6+y log(3/2) now i do i get x and y from this step. the answers are x=2.71 and y = 1.71 regards