Solving Spontaneous Reactions Homework: ΔG -270 kJ

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Discussion Overview

The discussion revolves around a homework problem concerning the spontaneity of the vaporization of boron carbide at a high temperature. Participants are tasked with calculating the Gibbs free energy change (ΔG) using given values and determining if the process is spontaneous based on the reaction conditions provided.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The initial calculation of the reaction quotient (Q) was attempted, but the absence of volume information was noted as a limitation.
  • One participant calculated Q as 1*10^-21 and applied it in the ΔG equation, resulting in ΔG = 1.044*10^6 J.
  • Another participant requested the expression for the reaction quotient.
  • A participant pointed out that the activity of solids is assumed to be 1, indicating they should not be included in the reaction quotient.
  • There was uncertainty expressed regarding the treatment of solids in the context of the reaction and their contribution to concentration calculations.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the correct approach to calculating ΔG, particularly regarding the treatment of solids in the reaction quotient and the implications of missing volume information.

Contextual Notes

Limitations include the lack of volume data necessary for concentration calculations and the assumption about the activity of solids in the reaction quotient.

Who May Find This Useful

Students studying thermodynamics, particularly those interested in Gibbs free energy and reaction spontaneity in chemical systems.

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Homework Statement


At 2600 K, ΔG° = 775 kJ for the vaporization of boron carbide:
B_{4}C (s) ⇔ 4 B (g) + C (s)

Find ΔG and determine if the process is spontaneous if the reaction vessel contains 4.00 mol of B_{4}C (s), 0.400 mol of C (s), and B (g) at a partial pressure of 1.0 x 10^-5 atm. At this temperature, R T = 21.6 kJ

2. The attempt at a solution

I first tried to find the reaction quotient but quickly realized that they did not give me the volume for this vessel. Thus, I just plugged everything into the reaction quotient (products/reactants) and got Q = 1*10^-21.

Then I plugged that into the ΔG = -RT*ln(Q) equation:

ΔG = -RT*ln(Q)
ΔG = -(21.6 J * 1000)*ln(1*10^-21)
ΔG = 1.044*10^6 J = 1044 kJ

The answer on the back of the book says that ΔG is in fact -270 kJ; how is this the answer? What mistake did I do in my calculations?
 
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Please write the reaction quotient.
 
Q=\frac{(pB)^4*[C]}{[B_{4}C]}
 
What do you know about solids in this context?
 
Um all I can figure out is that the solids are within a closed vessel and that the temperature also appears to be 2600 K since 21.6kJ/8.314 = 2600. The only issue regarding the solid is that I don't know what the volume is, which is prohibiting me from finding the concentration mol/L.

The only other thing is that maybe I have the wrong idea of how concentration of a solid works?
 
Activity of solids is assumed to be 1, so they are not present in the reaction quotient.
 

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