Solving Statistics Retour: 95% Confidence Interval & Hypothesis Test

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SUMMARY

This discussion focuses on constructing a 95% confidence interval for the variance of serum cholesterol measurements and performing a hypothesis test on the population mean. The provided data includes 15 daily serum cholesterol measurements, with a known mean of 190 mg/dL. The confidence interval is calculated using the chi-squared distribution, specifically utilizing the formula involving sample variance and degrees of freedom. Additionally, a one-sample t-test is recommended for testing the hypothesis that the population mean equals 190 mg/dL at a 0.02 significance level.

PREREQUISITES
  • Understanding of confidence intervals and their construction
  • Familiarity with the chi-squared distribution and its application in variance analysis
  • Knowledge of hypothesis testing, specifically one-sample t-tests
  • Basic statistics terminology and concepts
NEXT STEPS
  • Learn how to calculate confidence intervals using the chi-squared distribution
  • Study the one-sample t-test and its application in hypothesis testing
  • Review sample variance calculations and their significance in statistical analysis
  • Explore statistical software options for performing variance and hypothesis tests
USEFUL FOR

Statisticians, data analysts, and anyone involved in quality control or laboratory measurements who seeks to understand confidence intervals and hypothesis testing in the context of serum cholesterol analysis.

Mafer
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I haven't touch statistics for year and now I came back to find I am totally lost.
Here is one of the question that I wish to know how to solve it, in terms of steps, so that I can gain back memory about it.

Part 1:
In a test of a laboratory's measurement of serum cholesterol, 15 samples containing the same known amount (190 mg/dL) of serum cholesterol are submitted for measurement as part of a larger batch of samples, one sample each day over a three-week period. Suppose that the following daily values in mg/dL for serum cholesterol for these 15 samples were reported from the laboratory:

180, 190, 197, 199, 210, 187, 192, 199, 214, 237, 188, 197, 208, 220, 239

Assume that the variance for the measurement of serum cholesterol is supposed to be no larger than 100 mg/dL. Construct the 95 percent confidence interval for this laboratory's variance. Does 100 mg/dL fall within the confidence interval? What might be an explanation for the pattern shown in the reported values?

Part 2:
For the same data, test the hypothesis that the measuring process works - that is, test the hyposthesis that the population mean of the values measured by this process equals 190 versus the alternative hypothesis that the population mean is not equal to 190 mg/dL. Perform the test at the 0.02 significance level.

I know it is a bit too much, but I am really very very lost and depressed, help.
 
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These types of questions are straightforward, you just have to look up the appropriate technique (and get familiar with the terminology). According to
http://www.fmi.uni-sofia.bg/vesta/Virtual_Labs/interval/interval6.html :
let S^2 be the sample variance of normally distributed data
let \chi^2_{n,a} be the number x such that if X has a \chi^2 distribution with n degrees of freedom , then P(X < x) = a.
then
\left(\frac{n-1}{\chi^2_{n-1,1-a/2}}S^2,\frac{n-1}{\chi^2_{n-1,a/2}}S^2\right)
is a 1-a confidence interval for the distribution variance. You can calculate this interval numerically using a table for the \chi^2 distribution or some stats software.

In part 2, you need to use a one-sample t-test.

If these terms are unfamiliar to you, you just need to review your stats book and look up what you don't remember.
 
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