Solving System of Equations with x,y,z in [0,pi/2)

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SUMMARY

The discussion focuses on solving a system of transcendental equations involving variables x, y, and z constrained within the interval [0, π/2). The specific equations presented are: tan(x) + sin(y) + sin(z) = 3x, sin(x) + tan(y) + sin(z) = 3y, and sin(x) + sin(y) + tan(z) = 3z. A notable solution identified is (x, y, z) = (0, 0, 0), although the general consensus is that finding other solutions analytically is not feasible due to the nature of the equations.

PREREQUISITES
  • Understanding of transcendental equations
  • Familiarity with trigonometric functions such as sine and tangent
  • Knowledge of interval notation and constraints
  • Basic algebraic manipulation skills
NEXT STEPS
  • Explore numerical methods for solving transcendental equations
  • Learn about fixed-point iteration techniques
  • Investigate graphical methods for visualizing solutions in trigonometric contexts
  • Study the properties of functions within the interval [0, π/2)
USEFUL FOR

Mathematicians, students studying calculus or algebra, and anyone interested in solving complex systems of equations involving trigonometric functions.

juantheron
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How can i solve system of equations , if x,y,z\in \left[0,\frac{\pi}{2}\right)\begin{cases}\tan x+\sin y+\sin z = 3x\\\sin x+\tan y+\sin z = 3y\\\sin x+\sin y+\tan z = 3z\end{cases}
 
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Hello, jacks!

How can i solve system of equations , if x,y,z \in \left[0,\tfrac{\pi}{2}\right)

\begin{array}{ccc}\tan x+\sin y+\sin z &amp;=&amp; 3x\\<br /> \sin x+\tan y+\sin z &amp;=&amp; 3y\\<br /> \sin x+\sin y+\tan z &amp;=&amp; 3z\end{array}
I don't think you can.
. . The equations are transcendental.

However, by inspection, (x,y,z) \,=\,(0,0,0) is a solution.
 

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