MHB Solving the Domain: sqrt(x^2+y^2-1)>0 and 1<= x^2+y^2 <=20

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The discussion focuses on combining the domain defined by the inequalities sqrt(x^2+y^2-1)>0 and 1<= x^2+y^2 <= 20. The first condition simplifies to 1 < x^2 + y^2, which leads to the combined requirement of 1 < x^2 + y^2 ≤ 20. This intersection clarifies the domain for further calculations. Participants express appreciation for the simplification, noting it will facilitate their work. Overall, the solution effectively merges the two inequalities into a single expression.
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Im trying to combine this domain into something of the form a>b and b<c however I cannot seem to convert this equation :/

Is it possible to convert this domain into a single expression??

The domain is

sqrt(x^2+y^2-1)>0 and 1<= x^2+y^2 <= 20

any ideas?? I've encountered this problem many times and I am unsure as to how to solve this. Is there a general formula to apply?
 
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The first condition:

$$\sqrt{x^2+y^2-1}>0$$

implies:

$$1<x^2+y^2$$

Because both conditions must be true (as implied by the "and" between them), we find the intersection of the implication of the first condition with the second condition, to find we require:

$$1<x^2+y^2\le 20$$

in order for both conditions to be satisfied.
 
Thanks this makes a lot of sense. Combining two like this makes a lot of sense. This will make all of my further calculations easier thank you :)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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