Solving the Haaland Equation for Re

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Homework Help Overview

The discussion revolves around using the Haaland equation to determine the Reynolds number (Re) in fluid mechanics. The original poster presents specific values for the friction factor, absolute roughness, and internal diameter, expressing confusion about solving the equation due to a lack of prior knowledge on the topic.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve the Haaland equation but expresses difficulty in understanding the right-hand side of the equation, particularly regarding logarithmic functions. Some participants question the poster's familiarity with algebra and logarithmic concepts, while others provide clarifications about the nature of logarithms and their inverses.

Discussion Status

The discussion is ongoing, with participants exploring the mathematical concepts involved in the equation. Some guidance has been offered regarding logarithmic functions, but there is no clear consensus on how to proceed with the problem itself.

Contextual Notes

The original poster indicates a lack of instruction on the necessary mathematical concepts, which may be impacting their ability to engage with the problem effectively.

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Homework Statement



Using the Haaland equation shown below, determine the Reynold number Re

Friction factor λ = 0.032mm = 0.000032m
Absolute roughness Ks = 1.5 x 10-6m
Internal bore diameter d= 0.04m

1/√ λ = -1.8log[(6.9/Re) + [(ks/d)/3.7]1.11]

I have tried to solve the above equation but haven't got a clue as I have not been taught to this level. Consequently it's a bit unfair. Someone tried to help me but confused me even more. I do know the answer but need to show how I got the answer.

Any help would be appreciated.
 
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It seems a bit surprising you'd be working with an equation like this if you haven't mastered basic algebra yet. Where are you getting stuck?
 
vela said:
It seems a bit surprising you'd be working with an equation like this if you haven't mastered basic algebra yet. Where are you getting stuck?

Basic algebra yes but other people are speaking about anti logs? The left hand side of the equation is easy but I am struggling with the first part of the right hand side.

1/√0.032=-1.8log[(6.9/Re)+[( 1.5 x 10-6/0.04)/3.7]1.11]

Any help would be appreciated.
 
The inverse of the log function is the exponential function ex.
 
Well, more generally, the inverse of the log base n function is the exponential nx. So, logn(nx) = x.
 

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