- #1
Ben Wood
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Hi Guys,
I've just started a HND Building Services Engineering course (for Work) and I have been given my first assignment for hand in on the 11th Nov 2014.
I've not completed any Maths or Physics since Secondary School - 18 years ago (and didn't really pay attention then!) and I'd appreciate a bit of help understanding the equation given to me rather than just getting the answer.
It is as follows: -
Using the Haaland Equation below, determine the Reynolds Number Re and state whether the flow through the pipe is laminar or turbulent given -
Friction Factor λ = 0.032mm
Absolute Roughness Ks = 1.5 x10-6m
Internal Bore Diameter d = 0.04m
1/√λ = -1.8log [ (6.9/Re) + ( (Ks/d) / 3.7)1.11)
I have the following so far: -
1/√(0.032) = -1.8log [ (6.9/Re) + ( 1.5 x10-6 / 3.7)1.11 ]
1/0.1788854382 = -1.8log [ (6.9/Re) + ( 3.75 x10-4 / 3.7)1.11 ]
5.59 = -1.8log [ (6.9/Re) + ( 1.013513514 x10-4 )1.11 ]
It's at this point I get stuck I'm afraid...
I have been given the answer by another student as Re = 1275.51 which determines that I have a Streamlined Laminar Flow but I want to be able to solve this myself and check his answer is indeed correct.
So any help in helping me understand how to proceed is much appreciated. I understand once I have worked out as much as I can, it's time to transpose the equation to find Re which also seems a little tricky to me
Thank you
Ben
I've just started a HND Building Services Engineering course (for Work) and I have been given my first assignment for hand in on the 11th Nov 2014.
I've not completed any Maths or Physics since Secondary School - 18 years ago (and didn't really pay attention then!) and I'd appreciate a bit of help understanding the equation given to me rather than just getting the answer.
It is as follows: -
Using the Haaland Equation below, determine the Reynolds Number Re and state whether the flow through the pipe is laminar or turbulent given -
Friction Factor λ = 0.032mm
Absolute Roughness Ks = 1.5 x10-6m
Internal Bore Diameter d = 0.04m
1/√λ = -1.8log [ (6.9/Re) + ( (Ks/d) / 3.7)1.11)
I have the following so far: -
1/√(0.032) = -1.8log [ (6.9/Re) + ( 1.5 x10-6 / 3.7)1.11 ]
1/0.1788854382 = -1.8log [ (6.9/Re) + ( 3.75 x10-4 / 3.7)1.11 ]
5.59 = -1.8log [ (6.9/Re) + ( 1.013513514 x10-4 )1.11 ]
It's at this point I get stuck I'm afraid...
I have been given the answer by another student as Re = 1275.51 which determines that I have a Streamlined Laminar Flow but I want to be able to solve this myself and check his answer is indeed correct.
So any help in helping me understand how to proceed is much appreciated. I understand once I have worked out as much as I can, it's time to transpose the equation to find Re which also seems a little tricky to me
Thank you
Ben