Solving the Helicopter Problem - What is the Answer?

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The discussion centers on a physics problem involving a helicopter carrying a 70kg package that accelerates upward before the rope is cut. The key debate is whether the package retains an upward velocity of 30 m/s or drops to 0 m/s immediately after the cut. The original poster argues that the package continues with an initial upward velocity of 30 m/s and accelerates downward due to gravity thereafter. They liken the situation to a passenger in a bus who continues moving forward when the bus brakes suddenly. The consensus among classmates appears to differ from the poster's view, leading to unresolved confusion about the physics involved.
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This problem led to a debate in my physics class, which was never resolved.

A helicopter holding a 70kg package from a rope 5m long is accelerating up at a rate of 5.2 m/s^2. Neglect air resistance. When the upward velocity of the helicopter is 30 m/s, the rope is cut and the helicopter continues to rise at a rate of 5.2 m/s^2. Determine the distance between the helicopter and package after 2 seconds.

The debate was over whether or not the package had a velocity of 0 or 30m/s after it was cut. I personally believed the package to follow a projectile path upward at a starting velocity of 30 m/s. Am I wrong?
 
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In my opinion the package would have an upwards velocity on 30m/s and be accelerationg downwards at g.
 
It is obvious that when the package starts falling it has an initial velocity of 30m/s, taking upwards as positive. Take for example a bus. If you are a passenger, and if the bus was traveling at a high speed and was forced to brake at a high deceleration, you would be flung forward because you are still traveling at the bus's initial velocity before the bus decelerates.
 
Yup, no debate about it: it still has the velocity given to it by the helicopter, as they were acting as one object initially.
 
Thank you all for helping me on this one. I thought that the package should have an initial velocity of 30 m/s. Unfortunately, i was the only one to think so :frown: . Oh well. Thanks again
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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