Solving the logistic growth model

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The logistic growth model is defined by the equation dx/dt = rx(1 - x/K), where r and K are constants. The discussion focuses on solving this equation, with an emphasis on using separation of variables as the appropriate method. Participants confirm that separating variables leads to an integral that can be solved using partial fractions. The integration process involves rearranging the equation to isolate x and dx on one side. Overall, the conversation provides guidance on the correct approach to derive the solution x(t) = K/(1 + ce^(-rt)).
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The logistic growth model is the following:

dx/dt=rx(1-x/K), with r and K and as constants, and x is a function of t.

I'm really not sure where to begin. First I tried separation of variables, but that didn't work out (and I don't even know if I was doing it right). Should I even be looking for an integration factor in solving this? It looks simple...but I guess I'm rusty in this.

The end result is supposed to be:

x(t)=K/(1+ce^-rt) c=[K-x(0)]/x(0)

Second, I tried deriving this equation and getting it to look like the previous equation, but I think I'm missing somethings.

So just a tip or hint that can push me down the right track would be great. Thanks a lot!
 
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Separation of variables is the right way to go. It gives you an x integral you can do easily by partial fractions. The rest is algebra. Get started and if you get stuck let us know.
 
So separation of variables in this case would be A(t)dt+B(x)dx=0. So I would have dx/rx=(1-x/K)dt. Then, I should integrate both sides? Is this the right track?
 
Put ALL of the x's on one side with the dx.
 
So I get dx/(rx(1-(x/K))=dt. Then I should use partial fractions to integrate?
 
Exactly. Use partial fractions.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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