Solving the Mystery of sinh(-3) ≥ -3 or sinh(-3) ≤ -3?

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SUMMARY

The discussion centers on the inequalities involving the hyperbolic sine function, specifically sinh(-3). It establishes that sinh(-3) ≥ -3 based on the property exp(y) ≥ 1 + y for all y. However, a contradiction arises when manipulating the inequality, leading to sinh(-3) ≤ -3. The confusion highlights the importance of careful handling of inequalities, particularly when multiplying by negative numbers.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically sinh
  • Familiarity with exponential functions and their properties
  • Knowledge of inequality manipulation rules
  • Basic calculus concepts related to limits and continuity
NEXT STEPS
  • Study the properties of hyperbolic functions, focusing on sinh and cosh
  • Learn about the implications of manipulating inequalities, especially with negative multipliers
  • Explore the relationship between exponential functions and their inverses
  • Investigate common pitfalls in mathematical proofs involving inequalities
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Mathematics students, educators, and anyone interested in understanding hyperbolic functions and the nuances of inequality manipulation.

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I'm given the fact that exp(y) ≥ 1 + y for all y

I will use this for sinh. Since sinh = (exp(y) - exp(-y))/2 we have for y=3 as example:

sinh(3) ≥ 3 by subtracting the two inequalities

Instead for sinh(-3) I get:

sinh(-3) ≥ -3 (1)

But something is wrong here: Because if I take the first inequality sinh(3) ≥ 3 and multiply it by (-1) and switch around the inequality sinh and using the fact that
-sinh(3) = sinh(-3) I get:

sinh(-3) ≤ -3 (2)

This is clearly weird. Which of (1) and (2) is right and why is other one wrong?
 
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Careful when subtracting inequalities:

5 > 3
4 > 1

subtracting:
1 > 2 ?
 
ahh omg. Thanks LOL
 

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