Trigonometric Equations - Why Do I Always Get cos^3 or sin^3?

  • Thread starter Thread starter okh
  • Start date Start date
  • Tags Tags
    Trigonometric
Click For Summary

Homework Help Overview

The discussion revolves around solving trigonometric equations that involve cubic terms, specifically cos^3(x) and sin^3(x). Participants are exploring methods to manipulate these equations to facilitate solving them.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to solve two trigonometric equations but encounters difficulties with cubic terms. Some participants suggest substituting trigonometric identities to transform the equations into cubic forms. Others question how to approach solving cubic trigonometric equations, noting a lack of resources on this topic in their studies.

Discussion Status

Participants are actively discussing potential substitutions and methods for solving cubic equations. Some guidance has been provided regarding the rational root theorem and checking simple values, indicating a productive direction in the exploration of solutions.

Contextual Notes

There is mention of constraints related to the original poster's study materials, which do not cover cubic trigonometric equations, potentially limiting their approach to the problem.

okh
Messages
16
Reaction score
0

Homework Statement


I'm trying to solve two similar equations, but I can't go on.
This is the first one
http://img818.imageshack.us/img818/298/imageevsu.jpg

This is the second one:
http://img7.imageshack.us/img7/7812/imageowud.jpg

Homework Equations





The Attempt at a Solution


For the first one:
http://img855.imageshack.us/img855/4633/imagekhd.jpg

And for the second equation:
http://img12.imageshack.us/img12/2990/imageiag.jpg

And I'm stuck with these cos^3x and sin^3x. I think I should replace something...
 
Last edited by a moderator:
Physics news on Phys.org
okh said:

Homework Statement


I'm trying to solve two similar equations, but I can't go on.
This is the first one
http://img818.imageshack.us/img818/298/imageevsu.jpg

This is the second one:
http://img7.imageshack.us/img7/7812/imageowud.jpg

Homework Equations



The Attempt at a Solution


For the first one:
http://img855.imageshack.us/img855/4633/imagekhd.jpg

And for the second equation:
http://img12.imageshack.us/img12/2990/imageiag.jpg

And I'm stuck with these cos^3x and sin^3x. I think I should replace something...
For the first one, change sin2(x) to 1-cos2(x). You will have a cubic equation in cos(x).

For the second one, change cos2(x) to 1-sin2(x). You will have a cubic equation in sin(x).
 
Last edited by a moderator:
Okay, but how to solve cubic trigonometic equations?
I think I can get a quadratic equation, in some way. We are studying them, indeed, and there is nothing about cubic trigonometric equations in my book.
 
Well, if you don't do something you can't possibly get an answer!

Have you tried just checking some simple values? It helps sometimes to know the "rational root theorem". Any rational root, of the form p/q with integers p and q, of the polynoial a_nx^n+ a_{n-1}x^{n-1}+ a_1x+ a_0= 0 must have p evenly dividing a_0 and q evenly dividing a_n. That will reduce the number of trials. Of course, it is not necessary that a polynomial equation have rational roots but this one does.

Once you have a single root, say x= a, divide the cubic polynomial by x- a to reduce to a quadratic.
 

Similar threads

Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
9K
Replies
1
Views
2K