Solving Thin-Film Problem with Wavelengths 690 and 575nm

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The discussion revolves around determining the thickness of a thin film floating in water, given the observed wavelengths of 690nm and 575nm. The film has an index of refraction of 1.25, while water has an index of 1.33, leading to a phase shift of pi. Participants highlight the importance of constructive interference at the specified wavelengths, suggesting that two equations can be set up to relate the film's thickness to the wavelengths and the optical path difference. The conversation emphasizes that the problem focuses on reflection maxima rather than light transmission. Understanding these principles is crucial for solving the thin-film thickness problem effectively.
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Problem states: Wavelengths of 690 and 575nm are observed when white light is directed on a film floating in water. The index of the film is 1.25, and the index of water is 1.33.

What is the thichkness?

I know the phase is shifted by pi., but other than that I am not sure where to go with this problem!

Can I get a nudge in the right direction?

Thanks

--k
 
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I suppose I am only searching for the equation used to determine the answer.

I think that for thin films which have an index of refraction higher than the water, the thickness is wavelength over 4... but, for the situation of having an index lower than that of the water, I presume that some light makes it to/through the water...

Any help would be greatly appreciated!
 
Some light does make it through, even if the index is higher. But they're not asking about the amount of light transmitted or reflected - what they are giving you are the wavelengths where the reflection is a maximum. What is the name of chapter you working on now - interference? You have constructive interference at both wavelengths, which implies something about the thickness of the film - so you should be able to set up 2 equations relating wavelength, thickness and optical path difference between waves reflecting off the front and back surfaces of the film.
 
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