Thin film appears red, thickness of this part?

Click For Summary

Homework Help Overview

The problem involves a thin film of oil floating on water, where a portion of the film appears red due to constructive interference at a wavelength of 700 nm. The task is to determine the thickness of the film corresponding to this red appearance.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the phase shift due to the refractive index of oil and the implications for constructive interference. There is a debate about the appropriate integer value for m to use in the equation, with some questioning the clarity of the problem statement regarding the thickness.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the choice of m and its impact on the calculated thickness. Some guidance has been offered about selecting the smallest non-negative thickness, but no consensus has been reached on the specific value of m to use.

Contextual Notes

There is uncertainty about the wavelength of light in the oil compared to air, and participants are discussing how this affects the calculations. The problem does not specify whether to find the minimum thickness, leading to varied interpretations.

Cocoleia
Messages
293
Reaction score
4

Homework Statement


A thin film of oil (n=1.5) is floating on top of water. When looking directly at this film, a large portion appears red (700nm). What is the thickness of the red part of the layer?

Homework Equations

The Attempt at a Solution


Since n for oil > n for air, there will be a phase shift of lambda/2
There will be no phase shift for the next reflection, but it travels 2x the thickness of the film (2d)
Since it appears red, i said it was constructive interference. So we get mlambda = 2d + lambda/2
If they asked for minimum i would set m=0 and use the 700nm to solve for d, but they don't specify. What should i do?
 
Last edited by a moderator:
Physics news on Phys.org
You are right, there are different thicknesses (corresponding to different integer values of m) that would give constructive interference. I think they should have stated minimum thickness if that's what they wanted. The phrase "large portion of red" suggests that the thickness is very small, because with larger thicknesses the regions of interference maxima and minima tend to crowd together. But this still does not necessarily mean that you must pick the smallest thickness. So, I'm with you. The statement of the problem should have been clearer.

Note that if you choose m = 0 you will get a negative value for d. So, if you want the smallest thickness you would want to choose the smallest value of m for which you get a non-negative thickness.

Also, remember that lambda in the formula represents the wavelength of the light inside the film. So, you would not use 700 nm.
 
Cocoleia said:
So we get mlambda = 2d + lambda/2
Not quite. You are forgetting that in the oil the wavelength is shorter than in air (or vacuum). Your expression does not take into account this fact.
 
kuruman said:
Not quite. You are forgetting that in the oil the wavelength is shorter than in air (or vacuum). Your expression does not take into account this fact.
How would I find the correct wavelength?
 
Cocoleia said:
How would I find the correct wavelength?
 
TSny said:
Note that if you choose m = 0 you will get a negative value for d. So, if you want the smallest thickness you would want to choose the smallest value of m for which you get a non-negative thickness.
.
Can I choose m = 1 then? or will this no longer respect the conditions
 
In your equation mλf = 2d +λf/2, any positive integer value of m would correspond to constructive interference. m = 1 seems like the most natural choice. It will give the smallest thickness.
 

Similar threads

Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
5
Views
8K
Replies
2
Views
4K