MHB Solving third order recurrence relation

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To solve a third order recurrence relation with a characteristic polynomial factored as (x-1)^3, the characteristic root r=1 has a multiplicity of 3. The general solution will take the form of a linear combination of terms involving powers of the root and polynomial factors, specifically: a_0 + a_1*n + a_2*n^2, where a_0, a_1, and a_2 are constants determined by initial conditions. The next step involves using the initial conditions to find these constants. This approach effectively addresses the recurrence relation.
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I'm trying to solve a third order recurrence relation but not sure how. I wrote the characterisitc polynomial and factored it into [math](x-1)^3[/math]. Now what?
 
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Re: Solving third order reccurence relation

You have the characteristic root $r=1$ of multiplicity 3, so can you state what form the solution will have?
 
Greetings, I am studying probability theory [non-measure theory] from a textbook. I stumbled to the topic stating that Cauchy Distribution has no moments. It was not proved, and I tried working it via direct calculation of the improper integral of E[X^n] for the case n=1. Anyhow, I wanted to generalize this without success. I stumbled upon this thread here: https://www.physicsforums.com/threads/how-to-prove-the-cauchy-distribution-has-no-moments.992416/ I really enjoyed the proof...

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