MHB Solving third order recurrence relation

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To solve a third order recurrence relation with a characteristic polynomial factored as (x-1)^3, the characteristic root r=1 has a multiplicity of 3. The general solution will take the form of a linear combination of terms involving powers of the root and polynomial factors, specifically: a_0 + a_1*n + a_2*n^2, where a_0, a_1, and a_2 are constants determined by initial conditions. The next step involves using the initial conditions to find these constants. This approach effectively addresses the recurrence relation.
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I'm trying to solve a third order recurrence relation but not sure how. I wrote the characterisitc polynomial and factored it into [math](x-1)^3[/math]. Now what?
 
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Re: Solving third order reccurence relation

You have the characteristic root $r=1$ of multiplicity 3, so can you state what form the solution will have?
 
If there are an infinite number of natural numbers, and an infinite number of fractions in between any two natural numbers, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and... then that must mean that there are not only infinite infinities, but an infinite number of those infinities. and an infinite number of those...

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