Solving Two Body Problems - The Physics Classroom

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To solve the two-body problem involving a 5.0-kg and a 10.0-kg box, the key is to understand the forces acting on each box. The total force applied is 45.0 N, resulting in an acceleration of 3 m/s² for both boxes. To find the force acting between the boxes, consider the net force acting on the 10.0-kg box, which is 30 N (10 kg x 3 m/s²). This means the force exerted by the 5.0-kg box on the 10.0-kg box must be 30 N, as it is the only force acting on the 10.0-kg box. To calculate the force acting on the 5.0-kg box, use the formula F = ma, which will yield a different net force due to the interaction between the boxes.
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Hi,

I'm currently learning how to solve two body problems and I'm having a little trouble with that. My question regards a certain example I found in The Physics Classroom website that goes like this:

"A 5.0-kg and a 10.0-kg box are touching each other. A 45.0-N horizontal force is applied to the 5.0-kg box in order to accelerate both boxes across the floor. Ignore friction forces and determine the acceleration of the boxes and the force acting between the boxes."

I managed to find out the acceleration(3 m/s/s) but I don't understand how to find the force acting between the boxes. In the solution of this example they took the 10 kg boy and just calculated it's net force(30 N) and I undertood that but if I to calculate the net force acting on the 5 kg(15 N) body I'll get a different result entirly.

How can I determine the force acting between the boxes using the 5 kg box alone.

Thanks!
 
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I'm sorry but I bealive you forgot the attachment...
 
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