- #1

Remle

- 12

- 8

- Homework Statement
- A 25 kg box is being pushed down on by an applied force of 200 N inclined at 60° below the horizon.

- Relevant Equations
- Normal force: FN=m×g

- What is the acceleration of the box?
*Paper says the answer is*4 m/s^{2}. - What is the Normal force acting on the box?
*Paper says the answer is*418 N*.*

_{N}=F

_{g}=W. So, by definition the "original" Normal force is 245.25 N (am I correct?)

I calculated the F

_{ay}which is -173.205081 N, so I think that I have to add this two? Then the "new" F

_{N}and F

_{g}would be 418 N.

Also when I do my calcs for acceleration I end up with 8 m/s

^{2}not 4.

This is what I have: