Solving word problems using a system of equations (i'm guessing simultaneous).

[Daps]

you are laying the yellow and green brick road. the road is 1m wide and each brick is 500mm x 250mm. there are 3yellow bricks for every green brick. the road will be built with 12000 yellow bricks .how long will the road be?

Let x represent the no of yellow bricks
Let y represent the no of green bricks
I managed to get that x=3y-----equation 1
couldn't work equation 2 even though i could infer that y to be 4000bricks.
the 500mm x250mm brick (i'm thinking 8 of them is needed to fit into a square meter.

please can anyone enlighten me.
thanks

 

[skeeter]

you are laying the yellow and green brick road. the road is 1m wide and each brick is 500mm x 250mm. there are 3yellow bricks for every green brick. the road will be built with 12000 yellow bricks .how long will the road be?

Let x represent the no of yellow bricks
Let y represent the no of green bricks
I managed to get that x=3y-----equation 1
couldn't work equation 2 even though i could infer that y to be 4000bricks.
the 500mm x250mm brick (i'm thinking 8 of them is needed to fit into a square meter.

please can anyone enlighten me.
thanks

12000 yellow + 4000 green = 16000 bricks total

8 bricks for every square meter

16000/8 = 2000 square meters = 1 meter x 2000 meters

 

[Daps]

skeeter, thanks for your take on this question.sorry how did you work out they are suppose to have 8 bricks to fit in 1 square meter.

secondly what are the systems of equations (probably 2 equations).needed here.

Thanks replies are welcomed from everybody.

 

[skeeter]

given brick dimensions ...

500mm x 250mm = 0.5 m x 0.25 = 1/2 m x 1/4 m = 1/8 square meter

8 bricks x 1/8 square meter per brick = 1 square metersimultaneous equations? why make it more difficult?