Some questions on Green's Theorem.

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The discussion centers on the derivation of Green's Theorem, specifically addressing the integral equation presented in a PDF from Penn State. The user seeks clarification on the relationship between the integral of the partial derivative of a function N with respect to x and its evaluation at the boundaries, as outlined by the fundamental theorem of calculus. The user confirms that when integrating with respect to x, y is treated as a constant, validating the application of the theorem.

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yungman
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I am working on the derivation of Green's Theorem. I might have more question in later post. I am looking at this pdf file:

http://www.math.psu.edu/roe/230H/slides_14nov.pdf

In page 3, ##\int \int_R\frac{\partial N}{\partial x} dx dy=\int_c^d\int_a^{g(y)}\frac{\partial N}{\partial x} dx dy##

How is ##\int_a^{g(y)}\frac{\partial N}{\partial x} dx \;=\;N[g(y),y]\;-\;N(a,y)## as show in page 3? I don't know the steps to arrive to this.
 
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This is just the fundamental theorem of calculus, or the idea that an integral is an "antiderivative".
$$\int \frac{df(x)}{dx}\,dx =f(x) + C$$
$$\int_a^b \frac{df(x)}{dx}\,dx =f(b) - f(a)$$
When you do the "inside" integration over x, y is a constant, so N is just a function of x.
 
AlephZero said:
This is just the fundamental theorem of calculus, or the idea that an integral is an "antiderivative".
$$\int \frac{df(x)}{dx}\,dx =f(x) + C$$
$$\int_a^b \frac{df(x)}{dx}\,dx =f(b) - f(a)$$
When you do the "inside" integration over x, y is a constant, so N is just a function of x.

Thanks, yes I forgot about this. Just went back and studied up.
 

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