Sound waves - Destructive Interference

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Homework Help Overview

The problem involves two identical loudspeakers positioned 2 meters apart, producing sound waves that may interfere destructively. A detector is moved perpendicularly from one of the speakers, and the task is to determine the frequency below which no position along the line will experience destructive interference, given the speed of sound in air.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the lowest frequency and wavelength, considering how the path length difference changes as the detector moves. There is an exploration of substituting values into the equations for destructive interference and examining the implications of the derivative of the wavelength function.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on how to approach the calculations. There is recognition of the need to analyze the behavior of the wavelength function as the detector's position changes, and some participants have noted the function's maximum occurs at the boundary condition.

Contextual Notes

There is an ongoing discussion about the implications of setting n=0 in the context of the problem, and participants are reflecting on the behavior of the function derived from the path difference equation.

Saitama
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Homework Statement


Two identical loudspeakers are located at points A & B, 2m apart. The loudspeakers are driven by the same amplifier (coherent and are in the same phase). A small detector is moved out from point B along a line perpendicular to the line connecting A & B. Taking speed of sound in air as 332 m/s, find the frequency below which there will be no position along the line BC at which destructive interference occurs.

Homework Equations


The Attempt at a Solution


I am not sure how would I approach this problem. I started with calculating the path difference when the detector is at a distance x from its initial position,
\Delta x=\sqrt{4+x^2}-x
For destructive interference,
\sqrt{4+x^2}-x=\left(n+\frac{1}{2} \right)\lambda
where ##\lambda## is the wavelength of the wave.

I don't know how should I proceed from here.

Any help is appreciated. Thanks!
 

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Think:
What does lowest frequency mean for the wavelength?
How does the pathlength - difference change if the detector moves along x?

ehild
 
ehild said:
Think:
What does lowest frequency mean for the wavelength?
How does the pathlength - difference change if the detector moves along x?

ehild

Lowest frequency means highest wavelength. For that should I substitute n=0? And then I will get ##\lambda## as a function of x. So should I find maximum of this function?
 
Yes, do it...

ehild
 
ehild said:
Yes, do it...

ehild

I tried that but had no luck. Substituting n=0,
\lambda=2(\sqrt{4+x^2}-x)
Differentiating w..r.t x
\frac{d\lambda}{dx}=2(\frac{x}{\sqrt{4+x^2}}-1)=0
This equation has no solution for x. :(

EDIT: Looks like the function has its maximum value at x=0. And this gives me the right answer. Thanks ehild! :smile:
 
There is no local maximum, but the function decreases with x, and x≥0. The function takes the maximum at the boundary.

ehild
 
ehild said:
There is no local maximum, but the function decreases with x, and x≥0. The function takes the maximum at the boundary.

ehild

Yes I realized it when I examined the derivative. :)
 

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