- #1
exponent137
- 561
- 33
If we accelerate one body with mass m0 on a distance dx, then, we need energy dW:
dW = a m0 dx = dv/dt m dx = m0 dv v
Energy dW, which we gives weight dW= dm c^2
If we put this in differential equation, solvation is
dm/m0 = v dv /c^2
and
(m/m0)=exp(v^2/(2c^2))
But this calculation does not give that m is infinity at v = c.
What failing to my calculation?
(I know normal derivation of special relativity equation)
dW = a m0 dx = dv/dt m dx = m0 dv v
Energy dW, which we gives weight dW= dm c^2
If we put this in differential equation, solvation is
dm/m0 = v dv /c^2
and
(m/m0)=exp(v^2/(2c^2))
But this calculation does not give that m is infinity at v = c.
What failing to my calculation?
(I know normal derivation of special relativity equation)