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^{7}m above the surface of the Earth. Calculate the gravitational force of the Earth attracting the satellite. Give your answer to an appropriate number of significant figures.

Worked out to be F = 2.45 x 10

^{3}

The satellite in part (b)(i) is in a circular polar orbit. Show that the satellite would travel around the Earth three times every 24 hours.

The answer is F = (mv

^{2})/R+h where F = 2.45 x10

^{3}to find the speed first.

But no matter how I put that equation into the calculator, whether I use the valued stored in the calculator or type in exactly what it says, it is not 4.40 for speed but 4.439... so 4.44. Why is that?

This is a past exam question.