Speed of a Sneeze: Solve Homework Statement

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SUMMARY

The discussion centers on calculating the airspeed through the trachea during a cough, given a volume flow rate of 5.3 x 10-3 m3/s. The problem involves two scenarios: one with a normal trachea diameter of 19 mm and another with a contracted diameter of 7.8 mm. The user initially attempted to use the formula for volume flow rate, which is the product of area and velocity, but received incorrect results. The suggestion to work backwards was proposed as a potential solution to the problem.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically volume flow rate.
  • Knowledge of cross-sectional area calculations for circular tubes.
  • Familiarity with the speed of sound in air (343 m/s).
  • Basic algebra for solving equations and ratios.
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  • Learn how to calculate the cross-sectional area of a circle using the formula A = πr2.
  • Study the concept of compressible versus incompressible flow in fluid dynamics.
  • Explore the implications of varying diameters on flow speed and pressure using Bernoulli's principle.
  • Investigate the effects of air pressure and volume in respiratory mechanics.
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Students studying fluid dynamics, biology students focusing on respiratory mechanics, and educators looking for practical examples of volume flow rate applications.

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Homework Statement



When you cough, you expel air at high speed through the trachea and upper bronchi so that the air will remove excess mucus lining the pathway. You produce the high speed by this procedure: You breathe in a large amount of air, trap it by closing the glottis (the narrow opening in the larynx), increase the air pressure by contracting the lungs, partially collapse the trachea and upper bronchi to narrow the pathway, and then expel the air through the pathway by suddenly reopening the glottis. Assume that during the expulsion the volume flow rate is 5.3 x 10-3 m3/s. What multiple of the speed of sound xs (= 343 m/s) is the airspeed through the trachea if the trachea diameter (a) remains its normal value of 19 mm and (b) contracts to 7.8 mm?




2. Homework Equations / Solution Attempt

I applied the definition of volume flow rate = (area)(velocity) then divided that answer by 343 m/s to get the ratio but it says that it's wrong.
 
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Goatsenator said:
I applied the definition of volume flow rate = (area)(velocity) then divided that answer by 343 m/s to get the ratio but it says that it's wrong.

What was the answer?

Have you tried working backwards? it might help ; )
 

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