Speed of Perigee: Find Satellite Velocity at 750 km

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Discussion Overview

The discussion revolves around calculating the velocity of a satellite at perigee, given its apogee speed and altitudes. The problem involves concepts of orbital mechanics, specifically the application of conservation of energy and momentum in the context of satellite motion.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant suggests applying conservation of energy to find the satellite's speed at perigee.
  • Another participant agrees that conservation of energy can be used, but does not provide further details.
  • A participant emphasizes the need to calculate potential and kinetic energy at both perigee and apogee to derive the necessary equation.
  • There is a question raised about whether the gravitational parameter "M" needs to be found, indicating uncertainty about the required constants.
  • A later reply provides the gravitational parameter $\mu=GM=3.986004418(9)\times 10^{14}\text{ m}^3\text{s}^{-2}$ as a reference.
  • Another participant introduces the concept of conservation of momentum, presenting the equation $mv_Ar_A = mv_Pr_p$ as a potential approach.

Areas of Agreement / Disagreement

Participants generally agree on the applicability of conservation of energy for solving the problem, but there is uncertainty regarding the constants needed and the approach to take. Multiple viewpoints on how to proceed remain present.

Contextual Notes

There are unresolved questions about the necessity of specific gravitational constants and how they should be incorporated into the calculations. The discussion does not clarify the assumptions regarding the mass of the satellite or the nature of the orbits.

cbarker1
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Dear Everybody,

How to get started for this problem?
An Earth satellite has its apogee at 2,400 km above the surface of Earth and perigee at 750 km above the surface of Earth. At apogee its speed is 6,800 m/s. What is its speed at perigee (in m/s)? Earth's radius is 6,370 km (see the figure below, which is not drawn to scale)
11-3-p-056.png

Thanks,
Cbarker1
 
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Can we apply conservation of energy?
$$E=E_p + E_k = -\frac{GMm}{r} + \frac 12 mv^2$$
 
yes. We can use the conservation of energy.
 
Cbarker1 said:
yes. We can use the conservation of energy.

Good.
So what's stopping you from getting the answer?
 
:confused:

We need to find the potential energy and the kinetic energy at both the perigee and the apogee.
That should give us an equation from which we can find the answer. (Thinking)
 
I like Serena said:
:confused:

We need to find the potential energy and the kinetic energy at both the perigee and the apogee.
That should give us an equation from which we can find the answer. (Thinking)
Do we need to find "M"?
 
Cbarker1 said:
Do we need to find "M"?

I think we need to look it up.
More specifically $\mu=GM=3.986004418(9)\times 10^{14}\text{ m}^3\text{s}^{-2}$. See wiki.
 
conservation of momentum ...

$mv_Ar_A = mv_Pr_p$
 

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