Splitting an exponential complex number into real and imaginary parts

  • Thread starter dan5
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e-z2

where z is a complex number a+ib
 

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  • #2
I like Serena
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Welcome to PF, dan5! :smile:

Can you calculate -z2?

-z2 should be of the form c + id.

According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##.
So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.
 
  • #3
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Ahhh now I see, thanks to you, and to Euler!
 

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