- #1

- 9

- 0

e

where z is a complex number a+ib

^{-z2}where z is a complex number a+ib

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- Thread starter dan5
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- #1

- 9

- 0

e^{-z2}

where z is a complex number a+ib

where z is a complex number a+ib

- #2

I like Serena

Homework Helper

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Can you calculate -z

-z

According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##.

So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.

- #3

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Ahhh now I see, thanks to you, and to Euler!

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