- #1

- 9

- 0

e

where z is a complex number a+ib

^{-z2}where z is a complex number a+ib

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter dan5
- Start date

- #1

- 9

- 0

e^{-z2}

where z is a complex number a+ib

where z is a complex number a+ib

- #2

Homework Helper

MHB

- 16,350

- 257

Can you calculate -z

-z

According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##.

So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.

- #3

- 9

- 0

Ahhh now I see, thanks to you, and to Euler!

Share:

- Replies
- 7

- Views
- 386

- Replies
- 8

- Views
- 405

- Replies
- 7

- Views
- 745

- Replies
- 13

- Views
- 432

- Replies
- 13

- Views
- 987

- Replies
- 7

- Views
- 708

- Replies
- 38

- Views
- 2K

- Replies
- 2

- Views
- 539

- Replies
- 2

- Views
- 728

- Replies
- 2

- Views
- 126