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Splitting an exponential complex number into real and imaginary parts

  1. Jan 5, 2012 #1
    e-z2

    where z is a complex number a+ib
     
  2. jcsd
  3. Jan 5, 2012 #2

    I like Serena

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    Homework Helper

    Welcome to PF, dan5! :smile:

    Can you calculate -z2?

    -z2 should be of the form c + id.

    According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##.
    So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.
     
  4. Jan 5, 2012 #3
    Ahhh now I see, thanks to you, and to Euler!
     
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