e-z2 where z is a complex number a+ib
Jan 5, 2012 #2 I like Serena Homework Helper MHB 16,350 257 Welcome to PF, dan5! Can you calculate -z2? -z2 should be of the form c + id. According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##. So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.
Welcome to PF, dan5! Can you calculate -z2? -z2 should be of the form c + id. According to Euler's formula, we have ##e^{c+id} = e^c ( \cos d + i \sin d )##. So the real part is ##e^c \cos d## and the imaginary part is ##e^c \sin d##.