Spot Student Mistakes: 1/x < x < 1

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Homework Help Overview

The discussion revolves around identifying mistakes in the student's reasoning regarding the inequality \( \frac{1}{x} < x < 1 \). Participants are examining the implications of this inequality and the assumptions made about the variable \( x \).

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are analyzing the student's steps, particularly questioning the validity of the conclusions drawn from \( 1 < x^2 \) and \( 1 < x \). There is a focus on the assumption that \( x \) is positive and the implications of considering negative values.

Discussion Status

The discussion is active, with multiple participants contributing insights about the mistakes identified. Some guidance has been offered regarding the implications of the inequalities, and there is an exploration of whether there are multiple mistakes or just one. No consensus has been reached yet.

Contextual Notes

Participants note the importance of considering both positive and negative values of \( x \) in the context of the inequalities presented, which affects the validity of the student's conclusions.

garyljc
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Homework Statement


Spot the mistakes of a student


Homework Equations


1/x < x < 1
therefore 1<x^2
therefore 1<x
but x<1 therefore there are no solution


The Attempt at a Solution


the questions requires me to spot the mistake made by a student
so first of all
in the 2nd line , it reads 1<x^2 . this statement is wrong since the student assumes that x is always >0

i'm not too sure about about the second one , namely 1<x . Since it's related to the first one . What should i put ?
is there any other mistakes i have not spotted ?
 
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If you are given the statement x2 > 1, it doesn't necessarily imply that x>1. Consider the case where x=-5. x2=25 which is certainly greater than 1, but x>1 is not true. Again, the student has assumed that x is positive.
 
so does it mean there's only one mistake ?
 
If [tex]x > 0[/tex] you can't have

[tex] 0 < \frac 1 x < x < 1 [/tex]

because this is equivalent to

[tex] 0 < 1 < x^2 < x[/tex]
 
If 1/x < x < 1, it does not necessarily follow that 1 < x^2.

For example, for x=-1/2, we have -2 < -1/2 < 1, but 1 < 1/4 is false.

In fact, the implication is false for all -1 < x < 0.
 
If the previous post was directed at mine, you missed one of my points.
I said
If [tex]x > 0[/tex] you can't have

[tex] 0 < \frac 1 x < x < 1[/tex]

because (if you multiply through the inequality by [tex]x[/tex]) then you would have

[tex] 0 < 1 < x^2 < x[/tex]

My initial comment ruled out negative values from consideration. logarithmic, if I misunderstood you post by assuming it was meant at me, I apologize.
 

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