flyingpig
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Why do ideal springs stop at xf = 0? We have friction in this problem, does that mean it really doesn't stop at xf = 0, but xf < 0?
The problem involves a dynamics scenario where a box is acted upon by a spring and friction on a horizontal plane. The box has a mass of 12 kg and is initially at rest, compressed by a spring with a hardness coefficient of 800 N/m. The task is to calculate the velocity of the box at a certain point and the distance it travels before stopping.
The discussion is ongoing, with participants exploring various interpretations of energy conservation and friction's role in the problem. Some have provided insights into the energy formulas, while others are still grappling with the concepts and calculations involved.
Participants note the complexity of using multiple formulas step by step and the challenge of tracking the calculations. There is also mention of a time constraint due to impending exams, which may affect the depth of exploration in the discussion.
flyingpig said:Why do ideal springs stop at xf = 0? We have friction in this problem, does that mean it really doesn't stop at xf = 0, but xf < 0?