Stable equilibium of a potential

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SUMMARY

The discussion focuses on the potential energy function of a particle defined as ##U(x)=U_0[2(x/a)^2-(x/a)^4]##, where ##U_0## and ##a## are constants. Participants identify the stable equilibrium point at ##x=0## and discuss the angular frequency of oscillations, which can be approximated using harmonic motion principles. The minimum speed required for the particle to escape the potential well is derived, emphasizing the need to equate potential energy at the maxima with kinetic energy. Clarifications on the interpretation of the motion equations are also sought.

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Homework Statement


A particle of mass moving in one dimension has potential energy ##U(x)=U_0[2(x/a)^2-(x/a)^4]##, where #U_0# and ##a## are positive constants.
(i)What is the angular frequency ##w## of oscillations about the point of stable equilibrium?
(ii)What is the minimum speed the particle must have at the origin to escape to infinity?
(iii)At ##t=0## the particle is at the origin and its velocity is positive and equal in magnitude to the escape speed of part (d). Find ##x(t)##

The Attempt at a Solution


I have no idea about (i), though I know the stable equilibrium point is x=0.
My result of (ii) is ##\sqrt{\frac{-2U_0}{m}[2(x/a)^2-(x/a)^4]}##
But, here comes the problem. The speed at x=0 is 0, so it must stay at the origin forever.
I might get something wrong in obtaining the expression of (ii).
Any help would be appreciated.
 
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Plot the potential function. From that, you can understand what energy the particle needs to escape from the potential well.
As for (i) you need to find the angular frequency of small oscillations around x/a=0. If it is small, the fourth power can be ignored with respect to (x/a)^2 and the potential energy function approximates that of a spring.
I do not understand qestion (iii) What is x(x)? was not that v(x) instead?

ehild
 
The graph would be something like this ,
the potential at maxima (x=+-a) needs to be equated to KE
you will get velocity (min)
 

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