What is the Molarity of an Acid Sample Neutralized by NaOH?

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SUMMARY

The molarity of the acid sample, H2SO4, was calculated using the neutralization reaction with NaOH. It required 46.5 mL of 0.215M NaOH to neutralize 15.0 mL of the acid. The molarity of the H2SO4 solution is determined to be 0.139M. This calculation is based on the stoichiometry of the neutralization reaction and the definition of molarity.

PREREQUISITES
  • Understanding of molarity and its formula: M = moles of solute/liters of solution
  • Basic knowledge of acid-base neutralization reactions
  • Familiarity with stoichiometry in chemical reactions
  • Ability to perform unit conversions (mL to L)
NEXT STEPS
  • Review the concept of stoichiometry in acid-base reactions
  • Learn how to calculate moles from molarity and volume
  • Explore the properties of strong acids and bases
  • Study titration techniques and their applications in chemistry
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Chemistry students, educators, and anyone interested in understanding acid-base neutralization and molarity calculations.

kara
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It requires 46.5 mL of 0.215M NaOH to neutralize 15.0 mL of aqueous H2SO4. What was the molarity (M) of the acid sample?

I'm not quite sure how to approach this quesiton, if anyone has and starter tips please let me know.
 
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So for a I know that M (molarity) = moles of solute/liters of sol'n
 
Don't worry about it, I figured it out :D
 

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