Static friction on cars rounding curves with different masses and speeds

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courtney1121
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Car 1 with mass m rounds a curve of radius R traveling at a constant speed v. Car 2 with a mass 2m rounds a curve of radius 2R at a constant speed 2v. How does the magnitude F2 of the sideward static friction force acting on car 2 compare with the magnitude F1 of the sideward static friction force acting on car 1?

a. F1 = 4F2
b. F1 = 2F2
c. F1 = F2
d. F2 = 2F1
e. F2 = 4F1
 
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In order to get some help, you should show some efforts first.
 
sorry, I had listed my knowns but it didn't show

Anyways

I know that car 1 has half of everything car 2 has, so wouldn't it make sense that F2 = 2F1?
 
Ok the equation of centripetal forces is mv^2/r. The force of car one is simply mv^2/r and the centripteal force of car 2 would be 4mv^2/2r which equals 2mv^2/r. So Force of car 2 is twice that of force of car 1 so F1=2F2?
 
courtney1121 said:
Ok the equation of centripetal forces is mv^2/r. The force of car one is simply mv^2/r and the centripteal force of car 2 would be 4mv^2/2r which equals 2mv^2/r. So Force of car 2 is twice that of force of car 1 so F1=2F2?

The centripetal force exerted on the second car is 2m (2v)^2/(2R) = 4m v^2/R.
 
courtney1121 said:
what happened to 2R?

[tex]2m \frac{(2v)^2}{2R}= 2m \frac{4v^2}{2R}= 2m \frac{2v^2}{R}= 4m \frac{v^2}{R}[/tex]. I hope you agree on that. :smile:
 
Yes, since the sideward frictional force should balance the centripetal force.