Statistical mechanics problem about a paramagnet

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The discussion focuses on solving parts c and d of a statistical mechanics problem related to a paramagnet. For part c, a self-consistency equation for the effective magnetic field, B_eff, is established, which can be solved numerically by iterating guesses for B_eff. In part d, there is confusion regarding the treatment of a cubic term, with suggestions to simplify the hyperbolic tangent approximation. The correct approach for part d involves expanding to third order, but it requires careful consideration of assumptions, particularly that T/T_C is approximately 1. The conversation emphasizes the importance of correctly applying approximations and assumptions in deriving the expected results.
Clara Chung
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241093

I don't know how to solve part c and d.
Attempt:
c) B_eff=B+e<M>
Substitute T_c into the equation in part b,
=> (B_eff-B)/e = Nμ_B tanh(B_eff/(N*e*μ_B))
Then?
Thank you.
 
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Could you show what you got for part b?
 
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DrClaude said:
Could you show what you got for part b?
241154

I just rewrite the equation I found on part A to an equation containing B_eff only... is it what a self-consistency equation mean?...
 
Clara Chung said:
is it what a self-consistency equation mean?...
A self-consistency equation for ##B_\textrm{eff}## means that you get an equation for ##B_\textrm{eff}## that depends on itself. You could solve it numerically by guessing the value of ##B_\textrm{eff}## in the hyperbolic tangent, then calculating ##B_\textrm{eff}## on the left-hand side, and iterate until the value of ##B_\textrm{eff}## doesn't change anymore.

Your equation for (b) is correct. For (c), I think you can assume that ##B_\textrm{eff}## is small or, more properly
$$
\mu_\mathrm{B} B_\textrm{eff} \ll k T
$$
 
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DrClaude said:
A self-consistency equation for ##B_\textrm{eff}## means that you get an equation for ##B_\textrm{eff}## that depends on itself. You could solve it numerically by guessing the value of ##B_\textrm{eff}## in the hyperbolic tangent, then calculating ##B_\textrm{eff}## on the left-hand side, and iterate until the value of ##B_\textrm{eff}## doesn't change anymore.

Your equation for (b) is correct. For (c), I think you can assume that ##B_\textrm{eff}## is small or, more properly
$$
\mu_\mathrm{B} B_\textrm{eff} \ll k T
$$
I did part c using your hint
N7-rTdNZiC43p8GB6iHPa_nLYwV0aQlJI1sWdYlWcQiJqABjgP.png

However in part d), how to deal with the cube term T^3/T_c^3?
 
Clara Chung said:
I did part c using your hint
You didn't get the expected answer, which is given in the question. There is no need to keep the cubic terms.
 
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DrClaude said:
You didn't get the expected answer, which is given in the question. There is no need to keep the cubic terms.
Thank you, the answer I displayed above is for part d. The (T/T_C)^3 in the last line should be (T/T_C)^3/2. The expect term have no factor (T/T_C)^3/2, but there is one in my expression...
 
Above, you wrote
$$
B_\textrm{eff} = e N \mu_\mathrm{B} \left( \frac{B_\textrm{eff} \mu_\mathrm{B}}{kT} - \frac{B_\textrm{eff}^3 \mu_\mathrm{B}^3}{3 k^3T^3} \right)
$$
which means you took
$$
\tanh(x) \approx x - \frac{1}{3} x^3
$$
Try instead ##\tanh(x) \approx x##.
 
DrClaude said:
Above, you wrote
$$
B_\textrm{eff} = e N \mu_\mathrm{B} \left( \frac{B_\textrm{eff} \mu_\mathrm{B}}{kT} - \frac{B_\textrm{eff}^3 \mu_\mathrm{B}^3}{3 k^3T^3} \right)
$$
which means you took
$$
\tanh(x) \approx x - \frac{1}{3} x^3
$$
Try instead ##\tanh(x) \approx x##.
However, in part d the question says expand it to 3rd order?
 
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Clara Chung said:
However, in part d the question says expand it to 3rd order?
Sorry, I was looking at part (c). The solution to (d) is not obvious to me, I'll have to think a bit.
 
  • #11
In post #5, on the last line, you made an error when taking the square root.

To get the equation given in the problem, I had to assume also that ##T/T_C \approx 1##, as stated in the problem.
 
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