Statistical Mechanics problem from RK Pathria

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SUMMARY

The discussion focuses on the derivation of logarithmic terms in statistical mechanics, specifically referencing RK Pathria's "Statistical Mechanics." Participants explore how the equation involving partial derivatives transitions into a logarithmic form, emphasizing the relationship defined by the equation ## \frac{1}{y} \frac{ \partial {y}}{\partial x} = \frac{ \partial \; {\ln y}}{\partial x}##. The context involves energy exchange between two systems in equilibrium, denoted as E1 and E2, leading to a conjugate system energy E(0).

PREREQUISITES
  • Understanding of partial derivatives in calculus
  • Familiarity with logarithmic functions and their properties
  • Knowledge of energy concepts in thermodynamics
  • Experience with RK Pathria's "Statistical Mechanics" or similar texts
NEXT STEPS
  • Study the derivation of logarithmic identities in calculus
  • Explore energy exchange principles in thermodynamic systems
  • Review examples of partial derivatives in statistical mechanics
  • Investigate the implications of equilibrium states in multi-system analyses
USEFUL FOR

Students and professionals in physics, particularly those studying statistical mechanics, as well as educators looking to deepen their understanding of energy systems and mathematical derivations in this field.

Sudeb Sarkar
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How does the equation with partial derivative evolve into the next equation which also involves ln?
How do we get the logarithmic part?
E(0) = const = E1 +E2
where E1 and E2 are the energies of two separate systems in equilibrium and E(0) is the energy of the conjugate system where the two systems can exchange energy (only) with each other.

The Attempt at a Solution


The book used is RK Pathria's Statistical Mechanics, article 1.2
 

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Welcome to PF!

Note that ## \frac{1}{y} \frac{ \partial {y}}{\partial x} = \frac{ \partial \; {\ln y}}{\partial x}##

Looking at the equation before the equation with the logs, can you rearrange it so that you get terms of the form ##\frac{1}{y} \frac{ \partial {y}}{\partial x}##?
 
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TSny said:
Welcome to PF!

Note that ## \frac{1}{y} \frac{ \partial {y}}{\partial x} = \frac{ \partial \; {\ln y}}{\partial x}##

Looking at the equation before the equation with the logs, can you rearrange it so that you get terms of the form ##\frac{1}{y} \frac{ \partial {y}}{\partial x}##?
Thank you. I didn't know about that relation.
 

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