Steel Ball Density: Impact of Water Filling on Mercury Surface

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Homework Help Overview

The problem involves a steel ball floating on the surface of mercury in a half-filled container and examines the effects of adding water to the container. Participants explore the implications of the added weight of water on the ball's position in the mercury.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss whether the ball will sink further into the mercury with the added water and question the relationship between buoyancy and the ball's submersion level.

Discussion Status

Some participants have offered insights regarding the buoyant forces at play, while others express confusion about the mechanics involved. Multiple interpretations of the situation are being explored, indicating an ongoing inquiry into the problem.

Contextual Notes

There is uncertainty regarding the effects of buoyancy from the water on the ball and how it interacts with the mercury. Participants are grappling with the underlying principles of buoyancy and pressure in this context.

galuda
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Homework Statement


Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container is filled with water?


The Attempt at a Solution



Wouldn't the ball sink a little farther into the mercury with the added weight of the water on top of the ball? Or would it just stay where it's at? The mercury is obviously going to stay on bottom, and the steel ball is going to float in the water.
 
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You are correct. The steel ball should sink a little bit farther into the mercury due to the pressure from the water which will be above it.
 
Well apparently the answer was the ball remains partially submerged in mercury but not as deeply as before. I'm not sure I understand why that is, but in case anyone else is wondering, that's the way it is heh.
 
Hmm. Maybe it has to do with the buoyancy of the ball. The buoyant force of the water on the ball may cancel with some of the weight, thus causing less submergence in the mercury. Maybe something like this is the case? I don't see how this can be the case is the ball is on top of the mercury and no water is beneath the ball though...I won't say anything for sure, since I am not sure if this is the case.
 
Yeah, i don't get it either.
 

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