Step-by-Step Guide to Solving a Challenging Equation - Homework Help

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Homework Help Overview

The discussion revolves around solving a quadratic equation of the form S = at² + bt + c, using provided values for t and S. Participants are exploring how to derive the coefficients a, b, and c from the given data points.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to substitute specific values of t into the equation to form a system of equations. There are questions about the assumptions regarding the coefficients a and b, particularly whether they can be assumed to be zero.

Discussion Status

The discussion is active, with participants clarifying the implications of setting c to zero based on their equations. There is recognition of the correctness of the equations formed, but some participants express confusion about the assumptions being made regarding the coefficients.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available or the methods they can use to solve the problem. There is an emphasis on deriving relationships from the given values rather than providing direct solutions.

thomas49th
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Homework Statement



MathsQ1.jpg



Homework Equations



As in the image above

The Attempt at a Solution



I had a go but i rubbed it off the sheet.

Can someone take me through this step by step on how to solve it

Thanks
 
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What is your question? You are told exactly what to do!

You are told that the equation must be of the form
S= at2+ bt+ c.

You are given t and S values for 6 different values of t.
Putting the given x and t values into the equation above for 3 different values of t (t= 0, 2, 3, as they suggest, will do but the choice is yours) will give you 3 equations to solve for a, b, and c. (Taking t= 0 will get an especially easy equation!)
 
so

t=0: 0 = 0 + 0 + 0 (c will have to be 0 if a and b are)
t=1: 10 =a+b+c
t=2: 30 =4a+2b+c
is that right?
 
Last edited:
thomas49th said:
so

t=0: 0 = 0 + 0 + 0 (c will have to be 0 if a and b are)

but where does it say a and b are 0?

t=0: 0 = a.0 + b.0 +c and hence c=0

the other equations are correct
 
if t = 0
then a x t = 0
b x t = 0
so c must be 0 if the equation equals 0
 
Correct. Now use that you know c=0 in the other two equations
 
Huh? I thought the other 2 equations were right?

t=0: 0 = 0a + 0b + 0
t=1: 10 =a+b+c
t=2: 30 =4a+2b+c

cant I right them as that?
 
Yes they are correct but you now know that c = 0

so a+b+c=a+b

and

4a+2b+c=4a + 2b
 

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