Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Step on Weinberg's QM Book (pp. 154-155)

  1. Jan 20, 2014 #1
    Hello all!

    On the problem of taking elements of different (degenerated-)state vectors that do not vanish on the perturbation matrix, Weinberg uses the following approach, when dealing with the Zeeman effect:

    In this way, he goes from the first to the second equation shown as attachments.

    My main source of confusion arises by the fact that I can't see how can you align a (single-direction?) B vector with all the three (supposedly not parallel) axis of the coordinate system used. But I am surely completely missing the point in here.

    Can someone help me?
    Thanks for your time (:
     

    Attached Files:

  2. jcsd
  3. Jan 20, 2014 #2

    vanhees71

    User Avatar
    Science Advisor
    2016 Award

    Weinberg just puts the [itex]z[/itex]-axis in direction of the magnetic field and chooses the joint eigenbasis of the undisturbed hamiltonian, [itex]\vec{L}^2[/itex], and [itex]l_z[/itex].

    Note that due to the rotationinvariance of the undisturbed hamiltonian you are allowed to choose any direction as the [itex]z[/itex]-axis. For the perturbation it's just convenient to take it in the direction of [itex]\vec{B}[/itex].
     
    Last edited: Jan 20, 2014
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Step on Weinberg's QM Book (pp. 154-155)
Loading...