Stirling's Approximation for a factorial raised to a power

Click For Summary
The discussion focuses on applying Stirling's Approximation to the factorial raised to a power, specifically for ##[(\alpha - 1)!]^2##. The initial approach uses log identities to derive an expression, but there is uncertainty about its correctness. A participant suggests that instead of manipulating the logarithm directly, one should first apply Stirling's Approximation to ##(\alpha - 1)!## and then square the result for accuracy. This method is recommended as a more reliable way to approximate the factorial squared.
rmiller70015
Messages
110
Reaction score
1
Homework Statement
Find Stirling's Approximation for ##[(\alpha - 1)!]^2##
Relevant Equations
For large N: ##log(N!) \approx Nlog(N)-N##
Using log identities:
##log((\alpha - 1)!^2) = 2(log(\alpha - 1)!)##
Then apply Stirling's Approximation
##(2[(\alpha - 1)log(\alpha - 1) - (\alpha - 1)##
## = 2(\alpha -1)log(\alpha -1) - 2\alpha+2##

Is this correct? I can't find a way to check this computationally.
 
Physics news on Phys.org
rmiller70015 said:
Homework Statement:: Find Stirling's Approximation for ##[(\alpha - 1)!]^2##
Relevant Equations:: For large N: ##log(N!) \approx Nlog(N)-N##

Using log identities:
##log((\alpha - 1)!^2) = 2(log(\alpha - 1)!)##
Then apply Stirling's Approximation
##(2[(\alpha - 1)log(\alpha - 1) - (\alpha - 1)##
## = 2(\alpha -1)log(\alpha -1) - 2\alpha+2##

Is this correct? I can't find a way to check this computationally.
I don't think it's correct, and I get something different. If you want to approximate ##[(\alpha - 1)!]^2##, first use Stirling's to approximate ##(\alpha - 1)!##, and then square that result.
 
Last edited:
Thanks, that was bugging me.
 

Similar threads

Replies
4
Views
2K
  • · Replies 22 ·
Replies
22
Views
631
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
20
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
1K
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K