Stoichiometric ratio calculation

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Discussion Overview

The discussion revolves around calculating the stoichiometric ratio and amounts of various compounds needed to synthesize the superconducting compound Nd[O0.89F0.11]FeAs, as described in a referenced paper. Participants explore the challenges of balancing the reaction and determining the necessary quantities of Nd pieces, As, Fe, Fe2O3, and FeF3 powders for the synthesis.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant requests assistance in calculating the stoichiometric ratio and amounts of compounds needed for the synthesis of Nd[O0.89F0.11]FeAs, noting the lack of a balanced equation.
  • Another participant explains that while the reaction cannot be balanced in a standard way due to non-integer coefficients, the stoichiometry still applies, detailing the moles of each component in 1 mole of the compound.
  • A participant proposes a specific stoichiometric equation for the synthesis, suggesting amounts for Nd, As, Fe, Fe2O3, and FeF3 based on the earlier discussion.
  • A later reply expresses agreement with the proposed stoichiometric equation.

Areas of Agreement / Disagreement

Participants appear to agree on the proposed stoichiometric equation, but the initial request for help indicates uncertainty in the calculations and balancing of the reaction.

Contextual Notes

The discussion does not resolve the complexities of balancing reactions with non-integer coefficients or the specific calculations for the amounts of each compound required.

Rajini
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Dear all,

I am trying to synthesis a compound as given the paper below. Can someone help me of how to calculate the stoichiometric ratio and amount of each compound (i.e. Nd pieces, As, Fe, Fe2O3, FeF3 powders) required to prepare the same compound as in that paper. Especially I don’t know the balanced equation.

Preparation of superconducting compound is given in the following paper:
Doi: 10.1209/0295-5075/82/57002
The superconducting compound is Nd[O0.89F0.11]FeAs.
It is mentioned in that paper as follows:
Nd pieces, As, Fe, Fe2O3,FeF3 powders (the purities of all starting chemicals are better than 99.99%) were mixed together according to the nominal stoichiometric ratio of Nd[O0.89F0.11]FeAs, then ground thoroughly and pressed into small pellets.

thanks and regards, Rajini.
 
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You can't balance a reaction in a standard way, when the compound has non-integer coefficients. But the stoichiometry still holds - 1 mole of Nd[O0.89F0.11]FeAs contains 1 mole of Nd, 1 mole of Fe, 1 mole of As, 0.89 moles of O and 0.11 moles of F. Assume you are going to make 1 mole. Start calculating how much Fe2O3 you need to get correct amount of oxygen, then how much FeF3 for fluorides, then check how much Fe you already have and calculate how much Fe to add to make its total up to 1 mole. The rest should be obvious.
 
solved

Hello Borek,

I got your suggestion:
Is the following correct?
Nd + As + 0.3699Fe + 0.2967 Fe2O3 + 0.0367 FeF3 -> Nd[O0.89F0.11]FeAs.
I think I can now calculate grams of each compound reruired to prepare..
Regards, Rajini.
 
Looks OK to me.
 

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