Stoichiometry: Calculating Mass of HCl Neutralized by Milk of Magnesia

[FLgirl]

1. Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes stomach acid, primarily HCl, according to the following reaction:

Mg(OH)2(aq) + 2 HCl(aq) ---> 2 H2O(l) + MgCl2(aq)

What mass of HCl, in grams, can be neutralized by a dose of milk of magnesia caontaining 3.26g Mg(OH)2?




2. Mass A --> Amount A(in moles) --> Amount B(in moles) --> Mass B



3. The Attempt at a Solution : 3.26g Mg(OH)2 X 1mol Mg(OH)2 /34.01g Mg(OH)2 X 2 mol HCl/ 1 mol Mg(OH)2 X 36.46g HCl/ 1 molg HCl = 6.99


which is wrong, like I thought it would be. what's the right way to do this?

 

[FLgirl]

This forum really is so unhelpful.

 

[Borek]

Nobody answered in 2 hours and you already know we are unhelpful?

I have already answered your question elsewhere, is there a need to repeat it here? Check your molar masses.