Stoichiometry Help: Calculating NaOH for CO2 Removal in a Spacecraft

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SUMMARY

The discussion focuses on calculating the amount of sodium hydroxide (NaOH) required for CO2 removal in a spacecraft, based on the stoichiometric reaction: 2NaOH + CO2 → Na2CO3 + H2O. It is established that an average human discharges 592g of CO2 daily, necessitating a conversion of grams to moles using the molecular weight of CO2, which is 44.0096 g/mol. Participants emphasize the importance of stoichiometry in determining the precise amount of NaOH needed for effective CO2 scrubbing in confined environments like spacecraft.

PREREQUISITES
  • Understanding of stoichiometry and mole conversions
  • Familiarity with chemical reactions and balancing equations
  • Knowledge of molecular weights, specifically CO2 (44.0096 g/mol)
  • Basic chemistry concepts related to gas removal in closed systems
NEXT STEPS
  • Calculate the moles of NaOH required per mole of CO2 using stoichiometric ratios
  • Research the implications of CO2 removal on spacecraft life support systems
  • Explore alternative CO2 scrubbing methods and their efficiencies
  • Learn about the chemical properties and safety measures for handling NaOH
USEFUL FOR

Aerospace engineers, chemists, students studying chemical engineering, and anyone involved in life support systems for spacecraft will benefit from this discussion.

Rawlzilla
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As early as the 1938, the use of NAOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the reaction:

2NaOH+CO2--->Na2CO3+H2O

If the average human body discharges 592g of CO2 per day, how much NaOH is needed each day for each person in the spacecraft ?
 
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This is a homework problem and belongs in the homework section. Nevertheless, I'll help you answer it.

You know that stoichiometry only works with moles, right? So you need those grams to be moles. Here's a constant to help out a bit...

mw CO2 = C + 2*O = 44.0096 g/mol

Then find the moles of NaOH per CO2 and go from there.
 

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