- #1
th3whit3fang
- 8
- 0
1) K2CrO4 is produced by the reaction of FeCr2O4 with K2CO3 and O2 in a high temperature. This reaction also produces Fe2O3 and CO2.
If 169 kg FeCr2O4 reacts with 298 kg K2CO3 and 75 kg O2 and so it produces 194kg K2CrO4 then calculate the efficiency of this reaction.2) The equations is: 4 FeCr2O4 + 3 K2CO3 + 7 O2 --> 8 K2CrO4 + 2 Fe2O3 + 8 CO2
169 kg 298 kg 75 kg 194 kg 3) I first calculated the weights (2 Fe2O3 + 8 CO2) which were missing:
weight(2 Fe2O3 + 8 CO2) = (169 kg + 298 kg + 75 kg ) - 194 kg = 348 kg
and ther for the efficiency, i divided the weight of 8 K2CrO4 by 348 kg: 194 kg/ 348 kg = 55.7 %
It wasn't correct .. the correct answer is 66,2 %.
If 169 kg FeCr2O4 reacts with 298 kg K2CO3 and 75 kg O2 and so it produces 194kg K2CrO4 then calculate the efficiency of this reaction.2) The equations is: 4 FeCr2O4 + 3 K2CO3 + 7 O2 --> 8 K2CrO4 + 2 Fe2O3 + 8 CO2
169 kg 298 kg 75 kg 194 kg 3) I first calculated the weights (2 Fe2O3 + 8 CO2) which were missing:
weight(2 Fe2O3 + 8 CO2) = (169 kg + 298 kg + 75 kg ) - 194 kg = 348 kg
and ther for the efficiency, i divided the weight of 8 K2CrO4 by 348 kg: 194 kg/ 348 kg = 55.7 %
It wasn't correct .. the correct answer is 66,2 %.
Last edited by a moderator: