Stopping distances on a downward slope

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To determine the stopping distance of a 1500 kg car traveling at 30.0 m/s down a 10° slope with a coefficient of kinetic friction of 0.80, the kinetic energy (KE) must be balanced against the forces acting on the car. The frictional force and the component of gravitational force acting down the slope need to be calculated to find the net deceleration. The stopping distance can be derived from the equation that relates KE to the work done by friction and the gravitational force. It's important to resolve the gravitational force into components to accurately assess the impact of the slope on stopping distance. Understanding these forces is crucial for solving the problem effectively.
GayYoda
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Homework Statement


A 1500 kg car is traveling at a speed of 30.0 m s-1 when the driver slams on the brakes and skids to a halt. Determine the stopping distance if the car is traveling down a 10o slope. The coefficient of kinetic friction between the car
and the road is 0.80.

Homework Equations


F=ma

The Attempt at a Solution


i know that KE = Frictional force * stopping distance and i think in this case it is KE = frictional force * stopping distance - acceleration due to gravity * stopping distance but i can't work out what the acceleration due to gravity because of the slope
 
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Hints:

Does the car only have KE at the start of the skid?

You can resolve any vector such as the force of gravity into two component vectors at right angles to each other.
 
GayYoda said:
i know that KE = Frictional force * stopping distance
That is valid in a horizontal plane. What when the plane is at an angle ?
 

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