Stopping Distance and kinetic friction

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Homework Help Overview

The discussion revolves around calculating the stopping distance of a car under the influence of kinetic friction. The scenario involves a 1000 kg car traveling at 115.2 km/h with a frictional force of 4000 N applied when the automatic braking system is disabled. Participants are tasked with determining the stopping distance and whether the car will collide with a deer that appears 50 meters ahead.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between force, mass, and acceleration, with one suggesting a focus on momentum. Questions arise regarding the calculations of acceleration and stopping time, as well as the interpretation of the forces acting on the car.

Discussion Status

The discussion is ongoing, with participants questioning the original poster's calculations and assumptions. Some guidance is offered regarding the need to clarify the acceleration due to the frictional force, but no consensus has been reached on the correct approach or solution.

Contextual Notes

There is a noted lack of complete calculations from the original poster, which has led to confusion among participants. Additionally, the problem assumes no air resistance, which may influence the discussion of forces and motion.

David Donald
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Homework Statement



While traveling on the highway with your 1000kg car, at 115.2 km/h, where you’re ABS (automatic

braking system) is disabled. This means braking is relying solely on the friction of your tires with the road when they stop spinning. A dear jumps into the road 50 meters in front of you. If the frictional force created by you slamming on your brakes is 4000N. What will your final stopping distance be? Will you

hit the dear? Assume no air resistance.

Homework Equations



Kinematics?

The Attempt at a Solution


Sum of Forces in The X direction
(Force O' Car) - (Force O' Friction) = -ma

I solved for acceleration and got -5.8 m/s^2
plugging these into the kinematics equation I got a time... 5.52 seconds
plugging that into the Xf = Xo + Vox t + 1/2 a t^2 I got a distance which is wrong

what gives? what am i doing wrong?
 
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Maybe look at the momentum of the car. Units will be N sec. What would be a reasonable way to find seconds to stop under friction force in N?
I get something greater than 6 seconds.
 
David Donald said:

Homework Statement



While traveling on the highway with your 1000kg car, at 115.2 km/h, where you’re ABS (automatic

braking system) is disabled. This means braking is relying solely on the friction of your tires with the road when they stop spinning. A dear jumps into the road 50 meters in front of you. If the frictional force created by you slamming on your brakes is 4000N. What will your final stopping distance be? Will you

hit the dear? Assume no air resistance.

Homework Equations



Kinematics?

The Attempt at a Solution


Sum of Forces in The X direction
(Force O' Car) - (Force O' Friction) = -ma

I solved for acceleration and got -5.8 m/s^2
plugging these into the kinematics equation I got a time... 5.52 seconds
plugging that into the Xf = Xo + Vox t + 1/2 a t^2 I got a distance which is wrong

what gives? what am i doing wrong?
We have no idea; you didn't provide your complete calculations.

BTW, "you're" = "you are" and shouldn't be used to mean "your".
 
By the way...what is the acceleration caused by 4000N on a 1000kg car? If the car is starting at a constant velocity, that means acceleration of the car is zero...so what is the acceleration in the system? It is not -5.8 m/sec^2.
 

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