Stopping distances on a downward slope

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Homework Help Overview

The discussion revolves around determining the stopping distance of a car traveling down a slope, given its mass, initial speed, and the coefficient of kinetic friction. The problem involves concepts from dynamics and friction on inclined planes.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are exploring the relationship between kinetic energy and frictional force, questioning how to account for gravitational effects on a slope. There is a discussion about the validity of applying certain equations in a non-horizontal scenario.

Discussion Status

The conversation is ongoing, with some participants offering hints about resolving forces and questioning the assumptions made regarding kinetic energy on an incline. There is no explicit consensus yet, as various interpretations of the problem are being explored.

Contextual Notes

Participants are navigating the complexities introduced by the slope and the need to resolve forces into components, indicating potential gaps in the original problem setup or assumptions about the forces acting on the car.

GayYoda
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Homework Statement


A 1500 kg car is traveling at a speed of 30.0 m s-1 when the driver slams on the brakes and skids to a halt. Determine the stopping distance if the car is traveling down a 10o slope. The coefficient of kinetic friction between the car
and the road is 0.80.

Homework Equations


F=ma

The Attempt at a Solution


i know that KE = Frictional force * stopping distance and i think in this case it is KE = frictional force * stopping distance - acceleration due to gravity * stopping distance but i can't work out what the acceleration due to gravity because of the slope
 
Last edited:
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Hints:

Does the car only have KE at the start of the skid?

You can resolve any vector such as the force of gravity into two component vectors at right angles to each other.
 
GayYoda said:
i know that KE = Frictional force * stopping distance
That is valid in a horizontal plane. What when the plane is at an angle ?
 

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