Strong interaction and strangeness

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mrcotton
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Homework Statement



Printed problem: In the strong interaction, K⁻ + p → K⁰ + K⁺ + X, deduce the quark composition of and state the type of hadron represented by X, with two dotted answer lines below.



Homework Equations



This one has confused me,
I know that Baryon number has to be conserved so X has to be a baryon.
I can see how charge is conserved

The Attempt at a Solution



Handwritten particle reactions: K⁻ + p → K⁰ + K⁺ + Ξ⁻, and s ū + u u d → s d̄ + u s̄ + sss, with s̄ d written below.


I know this is the strong interaction. Is it a collision?
Is that where the energy for the extra two quarks come from?
Is there some strange conservation rule at play.
I know I made them all blue quarks but I only had one pen

Thanks and sorry for two question in one evening

D
 
mrcotton said:

Homework Statement



Printed exam question: In the strong interaction, K- + p → K0 + K+ + X, deduce the quark composition of, and state the type of, hadron represented by X, followed by two dotted answer lines.

Homework Equations



This one has confused me,
I know that Baryon number has to be conserved so X has to be a baryon.
I can see how charge is conserved

The Attempt at a Solution



Handwritten reactions: K⁻ + p ⇒ K⁰ + K⁺ + Ω⁻, and su̅ + uud ⇒ sd̅ + us̅ + sss, with a note below sd̅ reading s̄d.


I know this is the strong interaction. Is it a collision?
Is that where the energy for the extra two quarks come from?
Is there some strange conservation rule at play.
I know I made them all blue quarks but I only had one pen

Thanks and sorry for two question in one evening

D

First, it has to be a baryon, to conserve baryon number.
Second, it has to be negatively charged to conserve charge.
Third, it has to have a strangeness of -3 to conserve strangeness (strong interaction, so strangeness is conserved)

So, to be a negatively charged baryon with a negative strangeness of 3, it must have quark structure sss

So particle X is an Ω-

I think the mistake made is saying that K0 is anti-down strange. That is the anti-K0
The K0 is down anti-strange

:smile: