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rival95

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Question:

(n/3)^n < n! < (n/2)^n ; all integers n > 5

I proved the base case already and made the assumption of P(k) and am having difficulty knowing where to start on my proof of:

P(k+1): ( (k+1)/3)^k+1 < (k+1)! < ( (k+1)/2)^k+1

any help is greatly appreciated.