Struggling with Redox Reaction Equations?

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Discussion Overview

The discussion revolves around understanding and calculating electron transfer in redox reaction equations, specifically focusing on balancing half-equations. Participants are exploring methods to accurately determine the number of electrons involved in these reactions.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant expresses difficulty in calculating electron transfer in redox reactions, despite understanding oxidation states and other steps involved.
  • Another participant provides a link to a resource that may assist with balancing stoichiometry and oxidation numbers, though it is noted that this does not address the specific issue of balancing electrons.
  • A different participant offers a detailed explanation of balancing a half-equation, using an example to illustrate how to account for charges and electrons, but it remains unclear if this method resolves the original poster's confusion.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best method for calculating electron transfer, and the original poster's specific issue remains unresolved.

Contextual Notes

The discussion highlights the challenge of balancing electrons in half-equations, indicating a potential gap in understanding the relationship between oxidation states and electron transfer. There may be assumptions about prior knowledge that are not explicitly stated.

koosney@stcc
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hey I'm in yr 12 chemistry in Australia and I am having problems understanding redox reactions equations, i understand oxidation states and a little bit but i can't figure our about the electrons calculus, i can do the rest of the formula or steps but i cannot seem to be able to calculate the electron transfer accurately i was hoping some one would be able to help with methods or something.
thank you
 
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thanks but that doesn't really help me calculate how to balance electrons in half equations (thats the only problem i am having)
 
Hi,
I think I understand what you are having trouble with. When you are finished balancing a half-equation and let's say it looks like this:
Au3+(aq) + 2I−(aq) -> Au(s) + I2(s)
(3+ and - on left side are charges), so you have Au (3+) and I (2-) on left, and on right you don't have any charges as you can see. Notice that when you have a number in front like 2I, make sure you don't forget that number and see only one (-) at the top, you actually have (2-). So, now 2 out of 3 protons of Au on left will balance 2 electrons on left and you will be left with one proton (1+) on left. Then, if you want to balance electrons, you see that you have zero on right and you want same on left so you add one e- to the left to cancell the proton (+) you had left over after you balanced your equation. Same thing if you had in the end 4+ on left and 2- on right of equation you would add 6- to left to cancell 4+ and have 2- left over to balance the right side.

Hope this helps
Jaska
 

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