Stunt Driver's Car Jump: Minimum Speed Calculation and Angle Adjustment

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SUMMARY

The minimum speed required for a stunt driver to successfully jump over eight parked cars from a horizontal ramp with a vertical height of 1.5 meters and a horizontal distance of 20 meters is calculated to be 36.2 m/s. When the ramp is tilted upward at a 10-degree angle, the calculation for the new minimum speed becomes more complex, involving projectile motion equations. The discussion emphasizes the importance of understanding the time taken to reach maximum height to solve for the new speed.

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1. A stunt driver wants to make his car jump over eight cars parked side by side below a horizontal ramp. A.) With what minimum spped must he drive off the horizonal ramp? Vertical height of the ramp is 1.5 m above the cars, and the horizontal distance he must clear is 20 m
B.) If the ramp is now tilted upward so that takeoff angle is 10 degrees above the horizontal , what is the new minimum speed?



2.Used a lot of different ones.



3.I got 36.2 m/s for A.) but I can't find B.) at all.

Help please
 
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What have you tried so far. If you can do A then B is very similar.
 
How much time will it take for the car to reach it's maximum height?
 

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